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做网站直播的主播靠谱吗seo培训一对一

news 2025/7/12 13:56:34

做网站直播的主播靠谱吗,seo培训一对一,常州市新北区建设与管理局网站,东莞疫情最新动态场景： 混批名称相同合并混批名称，在混批名称相同条件下合并相同的混批类型；在混混批类型相同条件下合并相同的混批值；在混批值相同条件下合并相同的单位实现根据四个不同的key值，当四个key值对应相等时，合…

场景：混批名称相同合并混批名称，在混批名称相同条件下合并相同的混批类型；在混混批类型相同条件下合并相同的混批值；在混批值相同条件下合并相同的单位

实现根据四个不同的key值，当四个key值对应相等时，合并行。并且值合并前四col

想要实现的结果如下图：

解决方案：代码如下（先简单实现了合并。代码可以后续优化）

mergeMixedSku ({row, _rowIndex, column, visibleData}) {const fields = ['mixedName', 'mixedType', 'mixedValue', 'mixedValueUnit']const cellValue = row[column.property]if (cellValue && fields.includes(column.property)) {const prevRow = visibleData[_rowIndex - 1]let nextRow = visibleData[_rowIndex + 1]if (column.property === 'mixedName') {if (prevRow && prevRow[column.property] === cellValue) {return {rowspan: 0,colspan: 0}} else {let countRowspan = 1while (nextRow && nextRow[column.property] === cellValue) {nextRow = visibleData[++countRowspan + _rowIndex]}if (countRowspan > 1) {return {rowspan: countRowspan,colspan: 1}}}} else if (column.property === 'mixedType') {if (prevRow && prevRow[column.property] === cellValue &&prevRow.mixedName === row.mixedName) {return {rowspan: 0,colspan: 0}} else {let countRowspan = 1while (nextRow && nextRow[column.property] === cellValue &&nextRow.mixedName === row.mixedName) {nextRow = visibleData[++countRowspan + _rowIndex]}if (countRowspan > 1) {return {rowspan: countRowspan,colspan: 1}}}} else if (column.property === 'mixedValue') {if (prevRow && prevRow[column.property] === cellValue &&prevRow.mixedName === row.mixedName &&prevRow.mixedType === row.mixedType) {return {rowspan: 0,colspan: 0}} else {let countRowspan = 1while (nextRow && nextRow[column.property] === cellValue &&nextRow.mixedName === row.mixedName &&nextRow.mixedType === row.mixedType) {nextRow = visibleData[++countRowspan + _rowIndex]}if (countRowspan > 1) {return {rowspan: countRowspan,colspan: 1}}}} else if (column.property === 'mixedValueUnit') {if (prevRow &&prevRow[column.property] === cellValue &&prevRow.mixedName === row.mixedName &&prevRow.mixedType === row.mixedType &&prevRow.mixedValue === row.mixedValue) {return {rowspan: 0,colspan: 0}} else {let countRowspan = 1while (nextRow && nextRow[column.property] === cellValue &&nextRow.mixedName === row.mixedName &&nextRow.mixedType === row.mixedType &&nextRow.mixedValue === row.mixedValue) {nextRow = visibleData[++countRowspan + _rowIndex]}if (countRowspan > 1) {return {rowspan: countRowspan,colspan: 1}}}}}}